Let’s talk about the fundamental mathematical formulas that are utilised in everyday life as well as in textbooks. You must have studied the general **BODMAS rule **in your primary classes. But as you move up to grades from 6 to 10, you’ll encounter a variety of mathematical formulas based on ideas like algebra.

One can memorise all of the formulas by practising the questions and answers based on different formulas before taking the tests.

Following are some additional concepts using formulas:

- Fractions

- Percentage

- An equation for proportion

- Geometry

- Formulae for trigonometry, among many more.

**Basic Mathematics Formula**

The fundamentals of mathematics show how certain equations, such as the equation of forces, accelerations, or work done, can be used to solve mathematical problems. They are also utilised to offer mathematical solutions to difficulties that arise in our daily lives.

Equations come in a wide variety of forms and are used in many different areas of mathematics. However, the methods used to study them vary depending on their kind. It might be as straightforward as using the fundamental addition formula or as complex as integrating differentiation.

**Basic Math Formulas List**

The following lists of fundamental math formulas are provided:

**Percentage Formulas**

**Basic Geometry Formulas**

- Square’s perimeter is P = 4a.

where ‘a’ denotes the square’s side length

- Area of a Square is equal to A2

where ‘a’ denotes the square’s side length

- Rectangle’s area is equal to A = l b

Here, ‘l’ stands for length and ‘b’ for breadth.

- Triangle’s area is equal to A = 1/2 b h

where ‘b’ denotes the triangle’s base and ‘h’ denotes its height

- Trapezoid Area = A = 12 (b1 + b2) h

Where h = the height of the trapezium, and b1 and b2 are its bases.

- Circumference = A = r2

Circle circumference is equal to A2r.

where ‘r’ denotes a circle’s radius

- Cube Surface Area = S = 6a2

where ‘a’ denotes the cube’s side length

- Cylinder’s curved surface area is equal to 2rh.

Cylinder’s total surface area is equal to 2r(r + h).

Cylinder volume is V = r2h.

where ‘r’ denotes the radius of the cylinder’s base and ‘h’ denotes the cylinder’s height.

- A cone’s curved surface area is equal to rl.

Cone’s overall surface area is equal to r(r + l) = r[r + h2 + r2].

Cone Volume = V = 13 r2h

Here, ‘r’ denotes the radius of the cone’s base, and ‘h’ denotes the cone’s height.

S = 4r2 = Surface Area of a Sphere

- A sphere’s volume is equal to V = 4/3 r.

where r is the sphere’s radius

**Basic Arithmetic Formulas**

- Sum of values divided by the number of values is the arithmetic mean (average).

The easiest way to describe a mathematical formula is as an expression that was created after years and years of research on a certain subject. These mathematical formulas were created with the intention of providing accurate results in a matter of minutes or even seconds. This makes it possible to solve maths issues more quickly and improves your proficiency and quickness in doing so. As a result, Vedantu offers a thorough collection of Basic Math Formulas to aid in your understanding of the issues.

These formulas are especially helpful while preparing for competitive exams because they enable you to quickly and accurately answer questions. Although it is simple to add or subtract equations to solve large geometry or algebra problems, if you do not employ these mathematical formulae, the problem becomes too complicated.

**Question 1**

**To solve the equation 1/5 = 2/x for x, we can use algebraic manipulation to isolate x on one side of the equation.**

**Solution:**

First, we can cross-multiply both sides of the equation by x to get rid of the fraction:

1/5 * x = 2

Next, we can multiply both sides of the equation by 5 to isolate x:

x/5 = 10

Finally, we can multiply both sides of the equation by 5 to solve for x:

x = 50

Therefore, the solution to the equation 1/5 = 2/x is x = 50.

**Question 2**

**To add the fractions 2/5 and 6/7, we need to find a common denominator. The common denominator is the least common multiple of the denominators 5 and 7, which is 35.**

**Solution:**

To convert the fraction 2/5 to an equivalent fraction with a denominator of 35, we can multiply both the numerator and denominator by 7:

2/5 * 7/7 = 14/35

To convert the fraction 6/7 to an equivalent fraction with a denominator of 35, we can multiply both the numerator and denominator by 5:

6/7 * 5/5 = 30/35

Now that both fractions have the same denominator, we can add them:

14/35 + 30/35 = 44/35

However, this fraction is not in its simplest form, since the numerator and denominator have a common factor of 11. We can simplify the fraction by dividing both the numerator and denominator by 11:

44/35 ÷ 11/11 = 4/5

Therefore, the sum of the fractions 2/5 and 6/7 is 4/5.